第二高的薪水

SQL架构

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Create table If Not Exists Employee (Id int, Salary int)
Truncate table Employee
insert into Employee (Id, Salary) values ('1', '100')
insert into Employee (Id, Salary) values ('2', '200')
insert into Employee (Id, Salary) values ('3', '300')

编写一个 SQL 查询，获取 Employee 表中第二高的薪水（Salary） 。

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+----+--------+
| Id | Salary |
+----+--------+
| 1  | 100    |
| 2  | 200    |
| 3  | 300    |
+----+--------+

例如上述 Employee 表，SQL查询应该返回 200 作为第二高的薪水。如果不存在第二高的薪水，那么查询应返回 null。

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+---------------------+
| SecondHighestSalary |
+---------------------+
| 200                 |
+---------------------+

代码：

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# Write your MySQL query statement below
SELECT (
    SELECT DISTINCT
            Salary
    FROM
            Employee
    ORDER BY Salary DESC
    LIMIT 1 OFFSET 1
)
SecondHighestSalary
;